Evaluating Expressions With Exponents Using Substitution Of Variables Video Tutorial
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Evaluating Expressions With Exponents Using Substitution Of Variables
This tutorial will be able to show evaluate expressions when given values. You will need to use substitute the given values for expand the exponent notation. You learn how to find a product of a given expression.
Evaluating expressions with exponents using substitution of variables video involves evaluating expressions, exponents, expressions, product, substitution, substitution of variables, variables.
The video tutorial is recommended for 7th Grade, 8th Grade, 9th Grade, and/or 10th Grade Math students studying Algebra, Pre-Algebra, Pre-Calculus, and/or Advanced Algebra.
For a given combination of values for the free variables, an expression may be evaluated, although for some combinations of values of the free variables, the expression may be undefined. Thus an expression represents a function whose inputs are the values assigned the free variables and whose output is the resulting value of the expression.
Exponentiation is a mathematical operation, written an, involving two numbers, the base a and the exponent n. When n is a positive integer, exponentiation corresponds to repeated multiplication:
a1 = a
a2 = a × a
a3 = a × a × a
a4 = a × a × a × a
and so on.
An expression is a combination of numbers, operators, grouping symbols (such as brackets and parentheses) and/or free variables and bound variables arranged in a meaningful way which can be evaluated. Bound variables are assigned values within the expression (they are for internal use) while free variables can take on values from outside the expression.
Substitution Of Variables
In mathematics, substitution of variables (also called variable substitution or coordinate transformation) refers to the substitution of certain variables with other variables. Though the study of how variable substitutions affect a certain problem can be interesting in itself, they are often used when solving mathematical or physical problems, as the correct substitution may greatly simplify a problem which is hard to solve in the original variables. Under certain conditions the solution to the original problem can be recovered by back-substitution (inverting the substitution).