In mathematics, the logarithm of a number to a given base is the power or exponent to which the base must be raised in order to produce the number.

For example, the logarithm of 1000 to the base 10 is 3, because 10 raised to the power of 3 is 1000; the base 2 logarithm of 32 is 5 because 2 to the power 5 is 32.

For example, the logarithm of 1000 to the base 10 is 3, because 10 raised to the power of 3 is 1000; the base 2 logarithm of 32 is 5 because 2 to the power 5 is 32.

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At TuLyn, we have over 2000 math video tutorial clips including

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I bought a can of varnish

I bought a can of varnish and store at temperature of 40 degree. I change to another place where the temperature was 74degree. After 2 hours the temperature of the varnish was 58 degree .If the temperature of varnish must be 68 degree for best results ...

I bought a can of varnish and store at temperature of 40 degree. I change to another place where the temperature was 74degree. After 2 hours the temperature of the varnish was 58 degree .If the temperature of varnish must be 68 degree for best results ...

properties of logarithms

Is the logarithmic function j(x)=logbx a one on one function?

Is the logarithmic function j(x)=logbx a one on one function?

The number of books in a small library

The number of books in a small library increases according to the function

B = 5800 e^{0.04t}

where t is measured in ...

The number of books in a small library increases according to the function

B = 5800 e

where t is measured in ...

the graph of the function y =log^{5}x appears in which quadrants?

log 250-log 2=x

Solve:

2^{(x2)}=32^{(24x)}

2

solve log 2

7-52^{x}=-13

what are logarithms?

log_{3}+ log_{6}5

2logx+2log3=2

How to calculate using interpolation the number 0.785398

ln(1/e^{3})

Ln(p/302.1) = 113.04

log3 + log6^{5}

log y = 3 log(x) - 7

3(x+3)-7 simplify

log_{5} (3x-10) + log_{5} (7) = 2

log250 - log2 = x

log (x-3) = 2

log_{2}(6x+1)+log_{2}(x)=1

Logarithms.

I will be able to solve logarithms.

I need tutorals on logarithms.

I will be able to solve logarithms.

I need tutorals on logarithms.

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